Efficient Way to See if Linked Object in Same Project?

What would be the most efficient way to determine for a given object o and link lnk (an out-link or in-link) if the if the object othero at the other end of the link is in the same DOORS project as the given object o?

I want to avoid opening the module with the other object, if possible.

Maybe something like below? (Seems to work.)

Object o=current, othero
if (null o) {print "no object"; halt}
string o_projUID=uniqueID(getParentProject(module(o)))
Link lnk
ModName_ otherModRef
int lnkCnt=0
print "ID " o."Absolute Number" ":\n"
for lnk in o->"*" do        // for lnk in o<-"*" do
{
    lnkCnt++
    otherModRef=target(lnk) // otherModRef=source(lnk)
    if ( uniqueID(getParentProject(otherModRef)) == o_projUID)
    { 
        print "[" lnkCnt "] Link exists with object in SAME project!\n" 
    }
    else
    { 
        print "[" lnkCnt "] Link exists with object NOT in same project!\n" 
    }
}

Re: Efficient Way to See if Linked Object in Same Project?
PekkaMakinen - Wed Apr 05 13:48:03 EDT 2017

Do not have access to DOORS right now,  but getParentProject works also on ModName_s. With that function you would get two Project type values and compare those for equality.

Re: Efficient Way to See if Linked Object in Same Project?
strathglass - Wed Apr 05 14:28:34 EDT 2017

Yes, that is what I am doing for the target object: "otherModRef" is a ModName_ variable (don't need it for current object though).

So I guess this all seems to work OK, and seems pretty efficient...I can only process further the objects in the same project and open the other module as required.

Thanks.

Re: Efficient Way to See if Linked Object in Same Project?
PekkaMakinen - Thu Apr 06 01:44:43 EDT 2017

But you do not have to mess around with uniqueIDs

Object o=current, othero
if (null o) {print "no object"; halt}
Project currentProj = getParentProject(module(o))
Link lnk
ModName_ otherModRef
int lnkCnt=0
print "ID " o."Absolute Number" ":\n"
for lnk in o->"*" do        
{
    lnkCnt++
    otherModRef=target(lnk)
    if ((getParentProject(otherModRef)) == currentProj)
    {
        print "[" lnkCnt "] Link exists with object in SAME project!\n"
    }
    else
    {
        print "[" lnkCnt "] Link exists with object NOT in same project!\n"
    }
}

Re: Efficient Way to See if Linked Object in Same Project?
strathglass - Thu Apr 06 07:06:41 EDT 2017

You're right, thanks.

I think I had that because at some point I was dealing with only a project name, but clearly here I can just compare Projects!